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5w^2-3w-224=0
a = 5; b = -3; c = -224;
Δ = b2-4ac
Δ = -32-4·5·(-224)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-67}{2*5}=\frac{-64}{10} =-6+2/5 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+67}{2*5}=\frac{70}{10} =7 $
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